Why doesn't the moon fall into the sun at new moon? (this time with solution)
Suppose that it is noon. You jump up, and you fall back towards the earth. You do not fall into the sun. No surprise: although the sun is much more massive than the earth, it is much further away, so, near the surface of the earth, the gravitational field of the earth is much stronger than that of the sun.
So, how high would you have to go before the sun's gravitational attraction would win? At what point, on a line between the earth and the sun, are the two gravitational forces exerted by the sun and the earth equal and opposite? Let's say it is at a point d from the centre of the earth, and D from the centre of the sun. Obviously d is much less than D because the sun's mass (Ms = 1.99 x 1030 kg) is much greater than the mass of the earth (Me = 5.98 x 1024 kg). But just how far away is that point at d? For the calculation, we shall need the distance between the earth and the sun, which on average is re = 1.50 x 108 km.
Let's draw a diagram -- not to scale at first, because we still haven't done the calculation: let's put a mass m at distance d from the moon and D from the sun.
Now we just set the magnitude of the two gravititaional forces, acting on a mass m, equal to each other:
When we solve the quadratic, we get 260,000 km. (If you don't trust me, check it yourself.)
The puzzle:
Now the moon is 380,000 km from the earth. At new moon, it lies nearly on a line between the earth and the sun (during a solar eclipse, it lies exactly on this line). So, at new moon, will the moon fall into the sun?
- The calculation above is wrong: the moon will not be accelerating towards the sun, so there is nothing to worry about. [Explain error in the above.]
- The moon will be accelerating towards the sun but there is nothing to worry about because [see reason below].
- The moon will be accelerating towards the sun so my friend and I shall experience our last moonrise together over the ocean and we'll then sell our shares in tidal power stations.
(Look below for the solution.)
The solution:
The moon (380,000 km away) is about 400 times closer than the sun. In a year, there are about thirteen full moons. So a sketch of the path that the earth and the moon trace about the sun looks rather like this:
So, to a reasonable approximation, the moon traces a path around the sun that is approximately elliptical, with proportionally small perturbations in and out due to the gravitaitonal field of the earth. The curvature of the orbit is always concave towards the sun, although it is a lot less curved at new moon than at full moon.
So yes, the moon does fall towards the sun, but at irregular rates. The earth falls towards the sun at a much more regular rate, and so traces a more exactly elliptical orbit about the sun. But, to first order, the moon orbits the sun and is always falling towards it.
We can put it this way:
At full moon, the moon is accelerating towards the sun more rapidly than the earth is accelerating towards the sun. To an observer fixed on the earth, the moon is accelerating towards the earth.
At new moon, the moon is accelerating towards the sun, but less rapidly than the earth is accelerating towards the sun. To an observer fixed on the earth, the moon is accelerating towards the earth.
To an observer fixed with respect to the sun, however, the moon is always accelerating towards the sun.
The moon is perpetually falling towards the sun.